JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
An object is located at \(2\, km\) beneath the surface of the water. If the fractional compression \(\frac{\Delta V }{ V }\) is \(1.36\, \%,\) the ratio of hydraulic stress to the corresponding hydraulic strain will be ......... . [Given : density of water is \(1000\, kg m ^{-3}\) and \(\left. g =9.8 \,ms ^{-2} .\right]\)
- A \(1.96 \times 10^{7}\, Nm ^{-2}\)
- B \(1.44 \times 10^{7}\, Nm ^{-2}\)
- C \(2.26 \times 10^{9} Nm ^{-2}\)
- D \(1.44 \times 10^{9} \,Nm ^{-2}\)
Answer & Solution
Correct Answer
(D) \(1.44 \times 10^{9} \,Nm ^{-2}\)
Step-by-step Solution
Detailed explanation
\(P=h \rho g\) \(\beta=\frac{ p }{\frac{\Delta V }{ V }}=\frac{2 \times 10^{3} \times 10^{3} \times 9.8}{1.36 \times 10^{-2}}\) \(=1.44 \times 10^{9}\, N / m ^{2}\)
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