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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2021
  • Medium
  • Numerical

An \(npn\) transistor operates as a common emitter amplifier with a power gain of \(10^{6} .\) The input circuit resistance is \(100\, \Omega\) and the output load resistance is \(10\, K \Omega\). The common emitter current gain ' \(\beta\) ' will be............. (Round off to the Nearest Integer)

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Answer & Solution

Correct Answer

(B) \(100\)

Step-by-step Solution

Detailed explanation

\(10^{6}=\beta^{2} \times \frac{ R _{0}}{ R _{ i }}\)

\(10^{6}=\beta^{2} \times \frac{10^{4}}{10^{2}}\)

\(\beta^{2}=10^{4} \Rightarrow \beta=100\)

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