JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2021
- Medium
- Numerical
An \(npn\) transistor operates as a common emitter amplifier with a power gain of \(10^{6} .\) The input circuit resistance is \(100\, \Omega\) and the output load resistance is \(10\, K \Omega\). The common emitter current gain ' \(\beta\) ' will be............. (Round off to the Nearest Integer)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(100\)
Step-by-step Solution
Detailed explanation
\(10^{6}=\beta^{2} \times \frac{ R _{0}}{ R _{ i }}\)
\(10^{6}=\beta^{2} \times \frac{10^{4}}{10^{2}}\)
\(\beta^{2}=10^{4} \Rightarrow \beta=100\)
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