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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2023
  • Easy
  • Numerical

An inductor of inductance \(2\,\mu\,H\) is connected in series with a resistance, a variable capacitor and an \(AC\) source of frequency \(7\,kHz\). The value of capacitance for which maximum current is drawn into the circuit is \(\frac{1}{x} F\), where the value of \(x\) is \(.........\). \(\left(\right.\) Take \(\left.\pi=\frac{22}{7}\right)\)

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Answer & Solution

Correct Answer

(B) \(3872\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{2 \pi fC }=2 \pi fL\)

\(C =\frac{1}{4 \pi^2 f ^2 L }=\frac{1}{4 \times \pi^2 \times 49 \times 10^6 \times 2 \times 10^{-6}}\)

\(C =\frac{1}{3872}\,F\)

\(x =3872\)

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