JEE Mains · Maths · STD 11 - 14. probability
\(A\) and \(B\) alternately throw a pair of dice. \(A\) wins if he throws a sum of 5 before \(B\) throws a sum of 8 , and \(B\) wins if he throws a sum of 8 before \(A\) throws a sum of 5 . The probability, that \(A\) wins if A makes the first throw, is
- A \(\frac{8}{17}\)
- B \(\frac{9}{19}\)
- C \(\frac{9}{17}\)
- D \(\frac{8}{19}\)
Answer & Solution
Correct Answer
(B) \(\frac{9}{19}\)
Step-by-step Solution
Detailed explanation
For sum ' 5 ' \(\rightarrow(1,4),(2,3),(3,2)\) \((4,1) \Rightarrow P(A)=\frac{4}{36}\) For sum ' 8 ' \(\rightarrow(2,6),(3,5),(4,4)\) For sum ' 5 ' \(\rightarrow(1,4),(2,3),(3,2)\) \((4,1) \Rightarrow P(A)=\frac{4}{36}\) For sum ' 8 ' \(\rightarrow(2,6),(3,5),(4,4)\)…
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