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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
Statement \(-1\) : The system of linear equations \(x + \left( {\sin \,\alpha } \right)y + \left( {\cos \,\alpha } \right)z = 0\) \(x + \left( {\cos \,\alpha } \right)y + \left( {\sin \alpha } \right)z = 0\) \(x - \left( {\sin \,\alpha } \right)y - \left( {\cos \alpha } \right)z = 0\) has a non-trivial solution for only one value of \(\alpha \) lying in the interval \(\left( {0\,,\,\frac{\pi }{2}} \right)\) Statement \(-2\) : The equation in \(\alpha \) \(\left| {\begin{array}{*{20}{c}}
{\cos {\mkern 1mu} \alpha }&{\sin {\mkern 1mu} \alpha }&{\cos {\mkern 1mu} \alpha } \\
{\sin {\mkern 1mu} \alpha }&{\cos {\mkern 1mu} \alpha }&{\sin {\mkern 1mu} \alpha } \\
{\cos {\mkern 1mu} \alpha }&{ - \sin {\mkern 1mu} \alpha }&{ - \cos {\mkern 1mu} \alpha }
\end{array}} \right| = 0\) has only one solution lying in the interval \(\left( {0\,,\,\frac{\pi }{2}} \right)\)
- A Statement \(- 1\) is true, Statement \(-2\) is true,Statement \(-2\) is not correct explantion for Statement \(-1\)
- B Statement \(-1\) is true, Statement \(-2\) is true,Statement \(-2\) is a correct explantion for Statement \(-1\)
- C Statement \(- 1\) is true, Statement \(-2\) is false
- D Statememt \(-1\) is false, Statement \(-2\) is true.
Answer & Solution
Correct Answer
(C) Statement \(- 1\) is true, Statement \(-2\) is false
Step-by-step Solution
Detailed explanation
\({\Delta _1} = \left| {\begin{array}{*{20}{c}} 1&{\sin \alpha }&{\cos \alpha }\\ 1&{\cos \alpha }&{\sin \alpha }\\ 1&{ - \sin \alpha }&{\cos \alpha } \end{array}} \right|\)…
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