JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
If \(\left| {\begin{array}{*{20}{c}}{x - 4}&{2x}&{2x}\\{2x}&{x - 4}&{2x}\\{2x}&{2x}&{x - 4}\end{array}} \right| = \left( {A + Bx} \right){\left( {x - A} \right)^2},\) then the ordered pair \(\left( {A,B} \right) = \). . . . .
- A \(\left( { - 4,3} \right)\)
- B \(\left( { - 4,5} \right)\)
- C \(\left( {4,5} \right)\)
- D \(\left( { - 4, - 5} \right)\)
Answer & Solution
Correct Answer
(B) \(\left( { - 4,5} \right)\)
Step-by-step Solution
Detailed explanation
(2) Here, \(\left| {\begin{array}{*{20}{c}} {x - 4}&{2x}&{2x}\\ {2x}&{x - 4}&{2x}\\ {2x}&{2x}&{x - 4} \end{array}} \right| = \left( {A + Bx} \right){\left( {x - A} \right)^2}\) Put…
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