JEE Mains · Physics · STD 12 -6. Electromagnetic induction
In a fluorescent lamp choke (a small transformer) \(100 \;\mathrm{V}\) of reverse voltage is produced when the choke current changes uniformly from \(0.25 \;\mathrm{A}\) to \(0\;\mathrm{A}\) in a duration of \(0.025 \;\mathrm{ms} .\) The self-inductance of the choke (in \(\mathrm{mH})\) is estimated to be
- A \(15\)
- B \(10\)
- C \(20\)
- D \(25\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
\(\mathrm{V}=\left|\mathrm{L} \frac{\mathrm{di}}{\mathrm{dt}}\right|\) \(\Rightarrow \mathrm{L}=\frac{\mathrm{V}}{\left|\frac{\mathrm{di}}{\mathrm{dt}}\right|}=\cfrac{100}{\frac{0.25}{0.025 \times 10^{-3}}}=10 \mathrm{mH}\)
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