JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A \(30\) cm long solenoid has \(10\) turns per cm and area of \(5\) cm\(^2\). The current through the solenoid coil varies from \(2\) A to \(4\) A in \(3.14\) s. The e.m.f. induced in the coil is \(\alpha\times 10^{-5}\) V. The value \(\alpha\) is ________.
- A \(60\)
- B \(12\)
- C \(120\)
- D \(34\)
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
Given: Length of the solenoid, \(l = 30 \text{ cm} = 0.3 \text{ m}\) Number of turns per unit length, \(n = 10 \text{ turns/cm} = 1000 \text{ turns/m}\) Area of cross-section, \(A = 5 \text{ cm}^2 = 5 \times 10^{-4} \text{ m}^2\) Change in current,…
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