JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A particle is oscillating on the \(X-\) axis with an amplitude \(2\, cm\) about the point \(x_0 = 10\, cm\) with a frequency \(\omega \). A concave mirror of focal length \(5\,
cm\) is placed at the origin ( see figure) Identify the correct statements \((A)\) The image executes periodic motion \((B)\) The image executes non-periodic motion \((C)\) The turning points of the image are asymmetric w.r.t the image of the point at \(x =10\,cm\) \((D)\) The distance between the turning points of the oscillation of the image is \(\frac{{100}}{{21}}\)
- A \((B), (D)\)
- B \((B), (C)\)
- C \((A), (C), (D)\)
- D \((A), (D)\)
Answer & Solution
Correct Answer
(C) \((A), (C), (D)\)
Step-by-step Solution
Detailed explanation
When object is at \(8\,\mathrm{cm}\) Image \(V_{1}=\frac{f \times u}{u-f}=\frac{5 \times 8}{8-5}=-\frac{40}{3}\, \mathrm{cm}\) When object is at \(12\,\mathrm{cm}\) Image \(V_{2}=\frac{f \times u}{u-f}=\frac{5 \times 12}{12-5}=-\frac{60}{7}\, \mathrm{cm}\) Separation…
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