JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2019
- Medium
- MCQ
A steel wire having a radius of \(2.0\, mm\), carrying a load of \(4\, kg\), is hanging from a ceiling. Given that \(g = 3.1\pi \,m{s^{ - 2}}\) , what will be the tensile stress that would be developed in the wire?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(3.1 \times {10^6}\,N{m^{ - 2}}\)
Step-by-step Solution
Detailed explanation
Tensile stress in wire will be
\( = \frac{{Tensile\,force}}{{Cross\,section\,Area}}\)
\( = \frac{{mg}}{{\pi {R^2}}} = \frac{{4 \times 3.1\pi }}{{\pi \times 4 \times {{10}^{ - 6}}}}N{m^{ - 2}} = 3.1 \times {10^6}N{m^{ - 2}}\)
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