JEE Mains · Physics · STD 11 - 9.2 surface tension
A spherical soap bubble of radius \(3\,cm\) is formed inside another spherical soap bubble of radius \(6\,cm\). If the internal pressure of the smaller bubble of radius \(3\,cm\) in the above system is equal to the internal pressure of the another single soap bubble of radius \(r\,cm\). The value of \(r\) is.......
- A \(4\)
- B \(6\)
- C \(8\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(P_{2}-P_{0}=\frac{4 T}{6}\,and\,P_{1}-P_{2}=\frac{4 T}{3}\) \(\Rightarrow P_{1}-P_{0}=\frac{4 T}{2}=2\)
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