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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2021
  • Hard
  • Numerical

A ball will a speed of \(9\, m / s\) collides with another identical ball at rest. After the collision, the direction of each ball makes an angle of \(30^{\circ}\) with the original direction. The ratio of velocities of the balls after collision is \(x : y\) where \(x\) is........

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Answer & Solution

Correct Answer

(D) \(1\)

Step-by-step Solution

Detailed explanation

From conservation of momentum along y-axis.

\(\overrightarrow{ P }_{ iy }=\overrightarrow{ P }_{ fy }\)

\(0+0=m v_{1} \sin 30^{\circ} \hat{j}+m v_{2} \sin 30^{\circ}(-\hat{j})\)

\(mv _{2} \sin 30^{\circ}= mv _{1} \sin 30^{\circ}\)

\(v _{2}= v _{1}\) or \(\frac{ v _{1}}{ v _{2}}=1\)

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