JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2021
- Hard
- Numerical
A ball will a speed of \(9\, m / s\) collides with another identical ball at rest. After the collision, the direction of each ball makes an angle of \(30^{\circ}\) with the original direction. The ratio of velocities of the balls after collision is \(x : y\) where \(x\) is........
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
From conservation of momentum along y-axis.
\(\overrightarrow{ P }_{ iy }=\overrightarrow{ P }_{ fy }\)
\(0+0=m v_{1} \sin 30^{\circ} \hat{j}+m v_{2} \sin 30^{\circ}(-\hat{j})\)
\(mv _{2} \sin 30^{\circ}= mv _{1} \sin 30^{\circ}\)
\(v _{2}= v _{1}\) or \(\frac{ v _{1}}{ v _{2}}=1\)
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