JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A ball will a speed of \(9\, m / s\) collides with another identical ball at rest. After the collision, the direction of each ball makes an angle of \(30^{\circ}\) with the original direction. The ratio of velocities of the balls after collision is \(x : y\) where \(x\) is........
- A \(3\)
- B \(2\)
- C \(0\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
From conservation of momentum along y-axis. \(\overrightarrow{ P }_{ iy }=\overrightarrow{ P }_{ fy }\) \(0+0=m v_{1} \sin 30^{\circ} \hat{j}+m v_{2} \sin 30^{\circ}(-\hat{j})\) \(mv _{2} \sin 30^{\circ}= mv _{1} \sin 30^{\circ}\) \(v _{2}= v _{1}\) or…
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