JEE Mains · Maths · STD 12 - 9. differential equations
If a curve the \(y = f(x)\) passes through point \((1, -1)\) and satisfies the differential equation \(y\left( {1 + xy} \right)dx = xdy\) then \(f\left( { - \frac{1}{2}} \right) = \) . . . . .
- A \(\frac{2}{5}\)
- B \(\frac{4}{5}\)
- C \( - \frac{2}{5}\)
- D \( - \frac{4}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{5}\)
Step-by-step Solution
Detailed explanation
Given differential equation \(\mathrm{ydx}+\mathrm{xy}^{2} \mathrm{d} \mathrm{x}=\mathrm{xdy}\) \(\Rightarrow \frac{\mathrm{xdy}-\mathrm{ydx}}{\mathrm{y}^{2}}=\mathrm{xdx}\)…
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