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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

A proton, a neutron, an electron and an \(\alpha\,-\)particle have same energy. If \(\lambda_{ p }, \lambda_{ n }, \lambda_{ e }\) and \(\lambda_{\alpha}\) are the de Broglie's wavelengths of proton, neutron, electron and \(\alpha\) particle respectively, then choose the correct relation from the following

  1. A \(\lambda_{ p }=\lambda_{ n }>\lambda_{ e }>\lambda_{\alpha}\)
  2. B \(\lambda_{\alpha}<\lambda_{ n }<\lambda_{ p }<\lambda_{ e }\)
  3. C \(\lambda_{ e }<\lambda_{ p }=\lambda_{ n }>\lambda_{\alpha}\)
  4. D \(\lambda_{ e }=\lambda_{ p }=\lambda_{ n }=\lambda_{\alpha}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\lambda_{\alpha}<\lambda_{ n }<\lambda_{ p }<\lambda_{ e }\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{ h }{\sqrt{2 Em }}\) \(\lambda \propto \frac{1}{\sqrt{ m }}\) \(\therefore\lambda_{ e }>\lambda_{ p }>\lambda_{ n }>\lambda_{\alpha}\)
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