A proton, a neutron, an electron and an \(\alpha\,-\)particle have same energy. If \(\lambda_{ p }, \lambda_{ n }, \lambda_{ e }\) and \(\lambda_{\alpha}\) are the de Broglie's wavelengths of proton, neutron, electron and \(\alpha\) particle respectively, then choose the correct relation from the following

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Answer & Solution

Correct Answer

(B) \(\lambda_{\alpha}<\lambda_{ n }<\lambda_{ p }<\lambda_{ e }\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{ h }{\sqrt{2 Em }}\)

\(\lambda \propto \frac{1}{\sqrt{ m }}\)

\(\therefore\lambda_{ e }>\lambda_{ p }>\lambda_{ n }>\lambda_{\alpha}\)

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