JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\overrightarrow{\mathrm{a}}=2 \hat{\mathrm{i}}-3 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}, \overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-5 \hat{\mathrm{k}}\), and a vector \(\vec{c}\) be such that \(\vec{a} \times(\vec{b}+\vec{c})+\vec{b} \times \vec{c}=\hat{i}+8 \hat{j}+13 \hat{k}\). If \(\vec{a} \cdot \vec{c}=13\), then \((24-\vec{b} \cdot \vec{c})\) is equal to ...........
- A \(31\)
- B \(46\)
- C \(30\)
- D \(47\)
Answer & Solution
Correct Answer
(B) \(46\)
Step-by-step Solution
Detailed explanation
\( \vec{a} \times \vec{b}+\vec{a} \times \vec{c}+\vec{b} \times \vec{c}=(1,8,13) \) \( \vec{a} \times(\vec{a} \times \vec{b})+\vec{a} \times(\vec{a} \times \vec{c})+\vec{a} \times(\vec{b} \times \vec{c}) \) \( =\vec{a} \times(\hat{i}+8 \hat{j}+13 \hat{k})\)…
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