JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2019
- Hard
- MCQ
A ray of light \(AO\) in vacuum is incident on a glass slab at angle \(60^o\) and refracted at angle \(30^o\) along \(OB\) as shown in the figure. The optical path length of light ray from \(A\) to \(B\) is

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Answer & Solution
Correct Answer
(D) \(2a + 2b\)
Step-by-step Solution
Detailed explanation
From Snell's law
\(1 \sin 60^o=\mu \sin 30^o\)
\(\Rightarrow \mu=\sqrt{3}\)
Optical path \( = {\text{AO}} + \mu ({\text{OB}})\)
\( = \frac{{\text{a}}}{{\cos {{60}^o}}} + \sqrt 3 \frac{{\text{b}}}{{\cos {{30}^o}}}\)
\( = 2{\text{a}} + 2{\text{b}}\)
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