JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A ray of light \(AO\) in vacuum is incident on a glass slab at angle \(60^o\) and refracted at angle \(30^o\) along \(OB\) as shown in the figure. The optical path length of light ray from \(A\) to \(B\) is
- A \(2a + \frac{{2b}}{{\sqrt 3 }}\)
- B \(2a + \frac{{2b}}{3}\)
- C \(\frac{{2\sqrt 3 }}{a} + 2b\)
- D \(2a + 2b\)
Answer & Solution
Correct Answer
(D) \(2a + 2b\)
Step-by-step Solution
Detailed explanation
From Snell's law \(1 \sin 60^o=\mu \sin 30^o\) \(\Rightarrow \mu=\sqrt{3}\) Optical path \( = {\text{AO}} + \mu ({\text{OB}})\) \( = \frac{{\text{a}}}{{\cos {{60}^o}}} + \sqrt 3 \frac{{\text{b}}}{{\cos {{30}^o}}}\) \( = 2{\text{a}} + 2{\text{b}}\)
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