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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2019
  • Hard
  • MCQ

A ray of light \(AO\) in vacuum is incident on a glass slab at angle \(60^o\) and refracted at angle \(30^o\) along \(OB\) as shown in the figure. The optical path length of light ray from \(A\) to \(B\) is

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Answer & Solution

Correct Answer

(D) \(2a + 2b\)

Step-by-step Solution

Detailed explanation

From Snell's law

\(1 \sin 60^o=\mu \sin 30^o\)

\(\Rightarrow \mu=\sqrt{3}\)

Optical path \( = {\text{AO}} + \mu ({\text{OB}})\)

\( = \frac{{\text{a}}}{{\cos {{60}^o}}} + \sqrt 3 \frac{{\text{b}}}{{\cos {{30}^o}}}\)

\( = 2{\text{a}} + 2{\text{b}}\)

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