ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2021
  • Hard
  • MCQ

A radioactive sample is undergoing \(\alpha\) decay. At any time \(t_{1}\), its activity is \(A\) and another time \(t _{2}\), the activity is \(\frac{ A }{5}\). What is the average life time for the sample?

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{ t _{2}- t _{1}}{\ell n 5}\)

Step-by-step Solution

Detailed explanation

Let initial activity be \(A _{0}\)

\(A = A _{0} e ^{-\lambda t_{2}}....(i)\)

\(\frac{ A }{5}= A _{0} e ^{-\lambda t_{2}}....(ii)\)

\(( i ) \div ( ii )\)

\(5= e ^{\lambda\left(t_{2}-t_{1}\right)}\)

\(\lambda=\frac{\ell n 5}{t_{2}-t_{1}}=\frac{1}{\tau}\)

\(\tau=\frac{t_{2}-t_{1}}{\ell n \cdot 5}\)

Same subject
Explore more questions on app