JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2021
- Hard
- MCQ
A radioactive sample is undergoing \(\alpha\) decay. At any time \(t_{1}\), its activity is \(A\) and another time \(t _{2}\), the activity is \(\frac{ A }{5}\). What is the average life time for the sample?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\frac{ t _{2}- t _{1}}{\ell n 5}\)
Step-by-step Solution
Detailed explanation
Let initial activity be \(A _{0}\)
\(A = A _{0} e ^{-\lambda t_{2}}....(i)\)
\(\frac{ A }{5}= A _{0} e ^{-\lambda t_{2}}....(ii)\)
\(( i ) \div ( ii )\)
\(5= e ^{\lambda\left(t_{2}-t_{1}\right)}\)
\(\lambda=\frac{\ell n 5}{t_{2}-t_{1}}=\frac{1}{\tau}\)
\(\tau=\frac{t_{2}-t_{1}}{\ell n \cdot 5}\)
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