ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 10. vector algebra

Let \(ABC\) be a triangle whose circumcentre is at \(P\).If the position vectors \(A, B, C\) and \(P\) are \(\vec a,\vec b,\vec c\) and \(\frac{{\vec a + \vec b + \vec c}}{4}\) respectivey, then the position vector of the orthocentre of this triangle, is

  1. A \( - \left( {\frac{{\vec a + \vec b + \vec c}}{2}} \right)\)
  2. B \(\vec a + \vec b + \vec c\)
  3. C \(  \left( {\frac{{\vec a + \vec b + \vec c}}{2}} \right)\)
  4. D \(\vec 0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(  \left( {\frac{{\vec a + \vec b + \vec c}}{2}} \right)\)

Step-by-step Solution

Detailed explanation

Position vector of centriod \(\vec{G}=\begin{array}{c}{\vec{a}+\vec{b}+\vec{c}} \\ {3}\end{array}\) Position vector of circum centre \(\overrightarrow C = \begin{array}{*{20}{c}} {\vec a + \vec b + \vec c}\\ 4 \end{array}\)…