JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Two charged conducting spheres \(S_1\) and \(S_2\) of radii \(8\) cm and \(18\) cm are connected to each other by a wire. After equilibrium is established, the ratio of electric fields on \(S_1\) and \(S_2\) spheres are \(E_{S_1}\) and \(E_{S_2}\) respectively. The value of \(\dfrac{E_{S_1}}{E_{S_2}}\) is _______.
- A \(\dfrac{3}{2}\)
- B \(\dfrac{2}{3}\)
- C \(\dfrac{4}{9}\)
- D \(\dfrac{9}{4}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{9}{4}\)
Step-by-step Solution
Detailed explanation
When two conducting spheres are connected by a wire, charge flows until their potentials become equal. \(V_1 = V_2\) \(\dfrac{k Q_1}{R_1} = \dfrac{k Q_2}{R_2}\) The electric field on the surface of a conducting sphere is given by \(E = \dfrac{k Q}{R^2}\), which can be written as…
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