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JEE Mains · Maths · STD 12 - 11. three dimension geometry

If the shortest distance between the lines \(\frac{x-\lambda}{-2}=\frac{y-2}{1}=\frac{z-1}{1}\) and \(\frac{x-\sqrt{3}}{1}=\frac{y-1}{-2}=\frac{z-2}{1}\) is \(1 ,\) then the sum of all possible values of \(\lambda\) is :

  1. A \(0\)
  2. B  \(2 \sqrt{3}\)
  3. C \(3 \sqrt{3}\)
  4. D \(-2 \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B)  \(2 \sqrt{3}\)

Step-by-step Solution

Detailed explanation

Passing points of lines \(\mathrm{L}_1 \& \mathrm{~L}_2\) are \((\lambda, 2,1) \&(\sqrt{3}, 1,2)\) \((\lambda, 2,1) \&(\sqrt{3}, 1,2)\) \(S.D\)…