JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2020
- Medium
- Numerical
Visible light of wavelength \(6000 \times 10^{-8}\; \mathrm{cm}\) falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at \(60^{\circ}\) from the central maximum. If the first minimum is produced at \(\theta_{1},\) then \(\theta_{1}\) is close to.....\(^o\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(25\)
Step-by-step Solution
Detailed explanation
\(\sin \theta=\frac{2 \lambda}{\omega}\)
\(\sin 60^{\circ}=\frac{2 \lambda}{\omega}\)
\(\sin \theta_{1}=\frac{\lambda}{\omega}=\frac{\sqrt{3}}{4}\)
\(\theta_{1}=25^{\circ}\)
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