JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Two particles \(\mathrm{X}\) and \(\mathrm{Y}\) having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describes circular paths of radius \(R_1\) and \(R_2\) respectively. The mass ratio of \(\mathrm{X}\) and \(\mathrm{Y}\) is _______.
- A \(\left(\frac{R_2}{R_1}\right)^2\)
- B \(\left(\frac{R_1}{R_2}\right)^2\)
- C \(\left(\frac{R_1}{R_2}\right)\)
- D \(\left(\frac{R_2}{R_1}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{R_1}{R_2}\right)^2\)
Step-by-step Solution
Detailed explanation
\( \mathrm{R}=\frac{\mathrm{mv}}{\mathrm{qB}}=\frac{\mathrm{p}}{\mathrm{qB}}=\frac{\sqrt{2 \mathrm{~m}(\mathrm{KE})}}{\mathrm{qB}}=\frac{\sqrt{2 \mathrm{mqV}}}{\mathrm{qB}} \) \( \mathrm{R} \propto \sqrt{\mathrm{m}}\) \( \mathrm{m} \propto \mathrm{R}^2 \)…
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