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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 1988, 2024
  • Medium
  • MCQ

Two particles \(\mathrm{X}\) and \(\mathrm{Y}\) having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describes circular paths of radius \(R_1\) and \(R_2\) respectively. The mass ratio of \(\mathrm{X}\) and \(\mathrm{Y}\) is _______.

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Answer & Solution

Correct Answer

(B)  \(\left(\frac{R_1}{R_2}\right)^2\)

Step-by-step Solution

Detailed explanation

\( \mathrm{R}=\frac{\mathrm{mv}}{\mathrm{qB}}=\frac{\mathrm{p}}{\mathrm{qB}}=\frac{\sqrt{2 \mathrm{~m}(\mathrm{KE})}}{\mathrm{qB}}=\frac{\sqrt{2 \mathrm{mqV}}}{\mathrm{qB}} \)

\( \mathrm{R} \propto \sqrt{\mathrm{m}}\)

\( \mathrm{m} \propto \mathrm{R}^2 \)

\( \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\left(\frac{\mathrm{R}_1}{\mathrm{R}_2}\right)^2\)

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