JEE Mains · Maths · STD 12 - 1. relation and function
If \(f\left( x \right) = {\left( {\frac{3}{5}} \right)^x} + {\left( {\frac{4}{5}} \right)^x} - 1\) , \(x \in R\) , then the equation \(f(x) = 0\) has
- A no solution
- B one solution
- C two solution
- D more than two solutions
Answer & Solution
Correct Answer
(B) one solution
Step-by-step Solution
Detailed explanation
\(f\left( x \right) = {\left( {\frac{3}{5}} \right)^x} + {\left( {\frac{4}{5}} \right)^x} - 1\) Put \(f\left( x \right) = 0\) \( \Rightarrow 0 = {\left( {\frac{3}{5}} \right)^x} + {\left( {\frac{4}{5}} \right)^x} - 1\)…
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