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JEE Mains · Maths · STD 12 - 1. relation and function

If \(f\left( x \right) = {\left( {\frac{3}{5}} \right)^x} + {\left( {\frac{4}{5}} \right)^x} - 1\) , \(x \in R\) , then the equation \(f(x) = 0\) has

  1. A no solution
  2. B one solution
  3. C two solution
  4. D more than two solutions
Verified Solution

Answer & Solution

Correct Answer

(B) one solution

Step-by-step Solution

Detailed explanation

\(f\left( x \right) = {\left( {\frac{3}{5}} \right)^x} + {\left( {\frac{4}{5}} \right)^x} - 1\) Put \(f\left( x \right) = 0\) \( \Rightarrow 0 = {\left( {\frac{3}{5}} \right)^x} + {\left( {\frac{4}{5}} \right)^x} - 1\)…
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