JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A moving coil galvanometer has resistance \(50\,\Omega \) and it indicates full deflection at \(4\,mA\) current. A voltmeter is made using this galvanometer and a \(5\,k\Omega \) resistance. The maximum voltage, that can be measured using this voltamenter, will be close to ......\(V\)
- A \(15\)
- B \(20\)
- C \(10\)
- D \(40\)
Answer & Solution
Correct Answer
(B) \(20\)
Step-by-step Solution
Detailed explanation
\(G=50\, \Omega\) \(\mathrm{S}=5000 \,\Omega\) \(\mathrm{I}_{\mathrm{g}}=4 \times 10^{-3}\) \(\mathrm{V}=\mathrm{i}_{g}(\mathrm{G}+\mathrm{S})\) \(V=4 \times 10^{-3}(50+5000)\) \(=4 \times 10^{-3}(5050)=20.2\) \(volt\)
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