JEE Mains · Physics · STD 12 - 13. Nuclei
A piece of wood from a recently cut tree shows \(20\,decays\) per minute. A wooden piece of same size placed in a museum ( obtained from a tree cut many years back) shows \(2\,decays\) per minute. If half life of \(C^{14}\) is \(5730\, years\), then age of the wooden piece placed in the museum is approximately ........... \(years\)
- A \(10439\)
- B \(13094\)
- C \(19039\)
- D \(39049\)
Answer & Solution
Correct Answer
(C) \(19039\)
Step-by-step Solution
Detailed explanation
Given: \(\frac{\mathrm{d} \mathrm{N}_{0}}{\mathrm{dt}}=20\) decays \(/ \mathrm{mir}\) \(\frac{\mathrm{d} \mathrm{N}}{\mathrm{dt}}=2\) decays/min \(\mathrm{T}_{1 / 2}=5730 \mathrm{years}\) As we know, \(\mathrm{N}=\mathrm{N}_{0} \mathrm{e}^{-\lambda t}\)…
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