JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2020
- Easy
- MCQ
A plane electromagnetic wave of frequency \(25\; \mathrm{GHz}\) is propagating in vacuum along the \(z-\)direction. At a particular point in space and time, the magnetic field is given by \(\overrightarrow{\mathrm{B}}=5 \times 10^{-8} \hat{\mathrm{j}}\; \mathrm{T}\). The corresponding electric field \(\overrightarrow{\mathrm{E}}\) is (speed of light \(\mathrm{c}=3 \times 10^{8}\; \mathrm{ms}^{-1})\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(15 \hat{\mathrm{i}}\; \mathrm{V} / \mathrm{m}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E}=\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}}\)
\(=\left(5 \times 10^{-8} \hat{j}\right) \times\left(3 \times 10^{8} \hat{\mathrm{k}}\right)\)
\(=15 \hat{\mathrm{i}}\; \mathrm{V} / \mathrm{m}\)
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