JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Match List\(-I\) with List\(-II.\)
| List\(-I\) | List\(-II\) |
| \((a)\) Capacitance, \(C\) | \((i)\) \({M}^{1} {L}^{1} {T}^{-3} {A}^{-1}\) |
| \((b)\) Permittivity of free space, \(\varepsilon_{0}\) | \((ii)\) \({M}^{-1} {L}^{-3} {T}^{4} {A}^{2}\) |
| \((c)\) Permeability of free space, \(\mu_{0}\) | \((iii)\) \({M}^{-1} L^{-2} T^{4} A^{2}\) |
| \((d)\) Electric field, \(E\) | \((iv)\) \({M}^{1} {L}^{1} {T}^{-2} {A}^{-2}\) |
- A \((a) \rightarrow(i i i),(b) \rightarrow(i i),(c) \rightarrow(i v),(d) \rightarrow(i)\)
- B \((a) \rightarrow(i i i),(b) \rightarrow(i v),(c) \rightarrow(i i),(d) \rightarrow(i)\)
- C \((a) \rightarrow(iv),(b) \rightarrow(i i),(c) \rightarrow(iii),(d) \rightarrow(i)\)
- D \((a) \rightarrow(iv),(b) \rightarrow(iii),(c) \rightarrow(ii),(d) \rightarrow(i)\)
Answer & Solution
Correct Answer
(A) \((a) \rightarrow(i i i),(b) \rightarrow(i i),(c) \rightarrow(i v),(d) \rightarrow(i)\)
Step-by-step Solution
Detailed explanation
As we know \(q=C V\) \({[C]=\left[\frac{q}{V}\right]=\frac{(A \times T)^{2}}{M L^{2} T^{-2}}}\) \(=M^{-1} L^{-2} T^{4} A^{2}\) \({[E]=\left[\frac{F}{q}\right]=\frac{M L T^{-2}}{A T}}\) \(=M L T_{q}^{-3} A^{-1}\) \(F=\frac{q_{1} q_{2}}{4 \pi \epsilon_{0} r^{2}}\)…
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