JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2018
- Hard
- MCQ
The relative error in the determination of the surface area of a sphere is \(\alpha \). Then the relative error in the determination of its volume is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\frac{3}{2}\alpha \)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}
{\mathop{\rm Re}\nolimits} lative\,\,eroor\,\,in\,\,surface\,\,area,\\
\frac{{\Delta s}}{s} = 2 \times \frac{{\Delta r}}{r} = \alpha \,and\,relative\,error\,in\\
volume,\,\frac{{\Delta v}}{v} = 3 \times \frac{{\Delta r}}{r}\\
\therefore \,{\mathop{\rm Re}\nolimits} lative\,\,error\,in\,volume\,w.r.t\,relative\,error\,in\,area,\\
\frac{{\Delta v}}{v} = \frac{3}{2}\alpha
\end{array}\)
{\mathop{\rm Re}\nolimits} lative\,\,eroor\,\,in\,\,surface\,\,area,\\
\frac{{\Delta s}}{s} = 2 \times \frac{{\Delta r}}{r} = \alpha \,and\,relative\,error\,in\\
volume,\,\frac{{\Delta v}}{v} = 3 \times \frac{{\Delta r}}{r}\\
\therefore \,{\mathop{\rm Re}\nolimits} lative\,\,error\,in\,volume\,w.r.t\,relative\,error\,in\,area,\\
\frac{{\Delta v}}{v} = \frac{3}{2}\alpha
\end{array}\)
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