JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2023
- Medium
- Numerical
A block of mass \(10\,kg\) is moving along \(x\)-axis under the action of force \(F=5 x\; N\). The work done by the force in moving the block from \(x =2\,m\) to \(4\,m\) will be ............\(J\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(30\)
Step-by-step Solution
Detailed explanation
Work done \(=\int Fdx\)
\(\int \limits_2^4 5 x d x=5\left[\frac{ x ^2}{2}\right]_2^4\)
\(=\frac{5}{2}[16-4]\)
\(=30\,J\)
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