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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2023
  • Medium
  • Numerical

A block of mass \(10\,kg\) is moving along \(x\)-axis under the action of force \(F=5 x\; N\). The work done by the force in moving the block from \(x =2\,m\) to \(4\,m\) will be ............\(J\).

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Answer & Solution

Correct Answer

(A) \(30\)

Step-by-step Solution

Detailed explanation

Work done \(=\int Fdx\)

\(\int \limits_2^4 5 x d x=5\left[\frac{ x ^2}{2}\right]_2^4\)

\(=\frac{5}{2}[16-4]\)

\(=30\,J\)

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