JEE Mains · Physics · STD 11 - 2. motion in straight line
A horse rider covers half the distance with \(5\,m / s\) speed. The remaining part of the distance was travelled with speed \(10\,m / s\) for half the time and with speed \(15 m / s\) for other half of the time. The mean speed of the rider averaged over the whole time of motion is \(\frac{x}{7}\,m / s\). The value of \(x\) is
- A \(25\)
- B \(20\)
- C \(26\)
- D \(50\)
Answer & Solution
Correct Answer
(D) \(50\)
Step-by-step Solution
Detailed explanation
\(t _{ AB }=\frac{ x }{5 m / s }\) In motion \(BC\) \(x = d _1+ d _2\) where \(d _1 , d _2\) we the distance travelled with \(10\,m / s\) and \(15\,m / s\) respectively in equal time intervals \(\frac{' t^{\prime}}{2} \text { each }\) \(d_1=\frac{10 t}{2}, d_2=\frac{15 t }{2}\)…
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