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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2023
  • Hard
  • Numerical

A horse rider covers half the distance with \(5\,m / s\) speed. The remaining part of the distance was travelled with speed \(10\,m / s\) for half the time and with speed \(15 m / s\) for other half of the time. The mean speed of the rider averaged over the whole time of motion is \(\frac{x}{7}\,m / s\). The value of \(x\) is

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Answer & Solution

Correct Answer

(D) \(50\)

Step-by-step Solution

Detailed explanation

\(t _{ AB }=\frac{ x }{5 m / s }\)

In motion \(BC\)

\(x = d _1+ d _2\)

where \(d _1 , d _2\) we the distance travelled with \(10\,m / s\) and \(15\,m / s\) respectively in equal time intervals

\(\frac{' t^{\prime}}{2} \text { each }\)

\(d_1=\frac{10 t}{2}, d_2=\frac{15 t }{2}\)

\(d_1+d_2=x=\frac{t}{2}(10+15)=\frac{25 t }{2}\)

\(< v >=\frac{2 x }{\frac{ x }{5}+\frac{2 x }{25}}=\frac{2 \times 25}{5+2}=\frac{50}{7} m / s\)

Ans. : \(50\)

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