JEE Mains · Physics · STD 11 - 7. gravitation
A geostationary satellite is orbiting around an arbitary planet \(^{\prime} P ^{\prime}\) at a height of \(11 R\) above the surface of \(^{\prime} P ^{\prime} ,\) \(R\) being the radius of \(^{\prime} P .^{\prime}\) The time period of another satellite in hours at a height of \(2R\) from the surface of \(^{\prime} P ^{\prime}\) is \(........\).\(^{\prime} P ^{\prime}\) has the time period of \(24\, hours.\)
- A \(6 \sqrt{2}\)
- B \(\frac{6}{\sqrt{2}}\)
- C \(3\)
- D \(5\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(T \propto R ^{3 / 2}\) \(\frac{24}{ T }=\left(\frac{12 R }{3 R }\right)^{3 / 2} \Rightarrow T =3\, hr\)
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