JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor of capacitance \(90\ pF\) is connected to a battery of \(emf\) \(20\ V\). If a dielectric material of dielectric constant \(K = \frac{5}{3}\) is inserted between the plates, the magnitude of the induced charge will be.......\(n \) \(C\)
- A \(0.3\)
- B \(2.4\)
- C \(0.9\)
- D \(1.2\)
Answer & Solution
Correct Answer
(D) \(1.2\)
Step-by-step Solution
Detailed explanation
Charge on Capacitor, \(\mathrm{Q}_{i}=\mathrm{CV}\) After inserting dielectric of dielectric constant = \(\mathrm{K}\) \(\mathrm{Q}_{\mathrm{f}}=(\mathrm{k} \mathrm{C}) \mathrm{V}\) Induced charges on dielectric…
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