JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A current of 5A exists in a square loop of side \(\frac{1}{\sqrt{2}} \mathrm{~m}\). Then the magnitude of the magnetic field \(B\) at the centre of the square loop will be \(p \times 10^{-6} \mathrm{~T}\). where, value of p is _____ .
\(\left[\right.\) Take \(\left.\mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}\right]\).
- A 10
- B 8
- C 6
- D 4
Answer & Solution
Correct Answer
(B) 8
Step-by-step Solution
Detailed explanation
Let B be the magnetic field due to single side…
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