JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The locus of the mid point of the line segment joining the point \((4,3)\) and the points on the ellipse \(x^{2}+2 y^{2}=4\) is an ellipse with eccentricity
- A \(\frac{\sqrt{3}}{2}\)
- B \(\frac{1}{2 \sqrt{2}}\)
- C \(\frac{1}{\sqrt{2}}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{ x ^{2}}{4}+\frac{ y ^{2}}{2}=1\) Coordinate of \(D\) is \(\left(\frac{2 \cos \theta+4}{2}, \frac{\sqrt{2} \sin \theta+3}{2}\right) \equiv(h, k)\) \(\frac{2 h -4}{2}=\cos \theta\) \(\frac{2 k -3}{\sqrt{2}}=\sin \theta\) \((i)^{2}+(\text { ii })^{2}\), then we get…
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