JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A solid sphere is rolling on a horizontal plane without slipping. If the ratio of angular momentum about axis of rotation of the sphere to the total energy of moving sphere is \(\pi: 22\) then, the value of its angular speed will be \(...........\,rad / s\).
- A \(2\)
- B \(6\)
- C \(4\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
\(L =\left( I _{\text {com }}\right)(\omega) \text { and } K =\frac{1}{2}\left( I _{\text {com }}\right)\left(\omega^2\right)+\frac{1}{2} MV _{\text {com }}^2\)…
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