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JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A copper wire of length \(1.0\, m\) and a steel wire of length \(0.5\, m\) having equal cross-sectional areas are joined end to end. The composite wire is stretched by a certain load which stretches the copper wire by \(1\, mm\). If the Young's modulii of copper and steel are respectively \(1.0\times10^{11}\, Nm^{-2}\) and \(2.0\times10^{11}\, Nm^{- 2}\), the total extension of the composite wire is ........ \(mm\)
- A \(1.75\)
- B \(2\)
- C \(1.50\)
- D \(1.25\)
Answer & Solution
Correct Answer
(D) \(1.25\)
Step-by-step Solution
Detailed explanation
\({Y_c} \times \left( {\Delta {L_c}/{L_c}} \right) = {Y_s} \times \left( {\Delta {L_s}/{L_s}} \right)\) \( \Rightarrow 1 \times {10^{11}} \times \left( {\frac{{1 \times {{10}^{ - 3}}}}{1}} \right) = 2 \times {10^{11}} \times \left( {\frac{{\Delta {L_s}}}{{0.5}}} \right)\)…
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