JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2026
- Hard
- Numerical
When 300 J of heat given to an ideal gas with \(C _{ p }=\frac{7}{2} R\) its temperature raises from \(20{ }^{\circ} C\) to \(50^{\circ} C\) keeping its volume constant. The mass of the gas is (approximately) _________ g. \(( R =8.314 J / mol . K )\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) 0.48
Step-by-step Solution
Detailed explanation
\(C _{ v }= C _{ P }- R =\frac{5}{2} R\)
\(\Delta Q = nC _{ V } \Delta T\)
\(300= n \times \frac{5}{2} \times 8.314 \times 30\)
\(n =0.48\)
\(\frac{ m }{ M }=0.48\)
We cannot find mass (m) because molar mass (M) not given.
\(\Delta Q = nC _{ V } \Delta T\)
\(300= n \times \frac{5}{2} \times 8.314 \times 30\)
\(n =0.48\)
\(\frac{ m }{ M }=0.48\)
We cannot find mass (m) because molar mass (M) not given.
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