JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
When 300 J of heat given to an ideal gas with \(C _{ p }=\frac{7}{2} R\) its temperature raises from \(20{ }^{\circ} C\) to \(50^{\circ} C\) keeping its volume constant. The mass of the gas is (approximately) _________ g. \(( R =8.314 J / mol . K )\).
- A 0.48
- B 4.81
- C 48.1
- D 0.048
Answer & Solution
Correct Answer
(A) 0.48
Step-by-step Solution
Detailed explanation
\(C _{ v }= C _{ P }- R =\frac{5}{2} R\) \(\Delta Q = nC _{ V } \Delta T\) \(300= n \times \frac{5}{2} \times 8.314 \times 30\) \(n =0.48\) \(\frac{ m }{ M }=0.48\) We cannot find mass (m) because molar mass (M) not given.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- The correct truth table for the following logic circuit is _______.
JEE Mains 2024 Hard - A wire of length \(314\,cm\) carrying current of \(14\,A\) is bent to form a circle. The magnetic moment of the coil is \(........A- m ^{2}\). [Given \(\left.\pi=3.14\right]\)
JEE Mains 2022 Medium - For the given circuit the current through battery of \(6\,V\) just after closing the switch ' \(S\) ' will be\(.......A\).
JEE Mains 2022 Medium - If a charge \(q\) is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through the flat surface would be
JEE Mains 2022 Medium - A person of mass \(M\) is, sitting on a swing of length \(L\) and swinging with an angular amplitude \(\theta_0\). If the person stands up when the swing passes through its lowest point, the work done by him, assuming that his centre of mass moves by a distance \(l\, ( l < < L)\), is close toJEE Mains 2019 Hard
- A rod of length \(L\) has non-uniform linear mass density given by \(\rho(\mathrm{x})=\mathrm{a}+\mathrm{b}\left(\frac{\mathrm{x}}{\mathrm{L}}\right)^{2},\) where \(a\) and \(\mathrm{b}\) are constants and \(0 \leq \mathrm{x} \leq \mathrm{L}\). The value of \(\mathrm{x}\) for the centre of mass of the rod is atJEE Mains 2020 Hard
More PYQs from JEE Mains
- Let the image of the point \(P (1,2,6)\) in the plane passing through the points \(A (1,2,0), B (1,4,1)\) and \(C(0,5,1)\) be \(Q(\alpha, \beta, \gamma)\). Then \(\left(\alpha^2+\beta^2+\gamma^2\right)\) is equal to :JEE Mains 2023 Hard
- If \(\lim _{x \rightarrow 0} \frac{a x-\left(e^{4 x}-1\right)}{a x\left(e^{4 x}-1\right)}\) exists and is equal to \(b\), then the value of \(a-2 b\) is ....... .JEE Mains 2021 Hard
- If the lines \(x+y=a\) and \(x-y=b\) touch the curve \(y = x ^{2}-3 x +2\) at the points where the curve intersects the \(x\)-axis, then \(\frac{ a }{ b }\) is equal toJEE Mains 2020 Medium
- Let \(z\) be complex number such that \(\left|\frac{z-i}{z+2 i}\right|=1\) and \(|z|=\frac{5}{2} \cdot\) Then the value of \(|z+3 i|\) isJEE Mains 2020 Hard
- If \(\frac{d y}{d x}=\frac{2^{x+y}-2^{x}}{2^{y}}, y(0)=1\), then \(y(1)\) is equal to :JEE Mains 2021 Hard
- The set of all values of \(\lambda \) for which the system of linear equations \(x - 2y - 2z = \lambda x\) ; \(x + 2y + z = \lambda y\) ; \(-x - y = \lambda z\) has non zero solutions.JEE Mains 2019 Hard