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JEE Mains · Physics · STD 12 -6. Electromagnetic induction

A circular loop of radius \(20\text{ cm}\) and resistance \(2\ \Omega\) is placed in a time varying magnetic field \(\vec{B} = (2t^2 + 2t + 3)\text{ T}\). At \(t = 0\), for the plane of the loop being perpendicular to the magnetic field and, the induced current in the loop at \(t = 3\text{ s}\) is \(\dfrac{\alpha}{50}\text{ A}\). The value of \(\alpha\) is _______.
(Take \(\pi = 22/7\))

  1. A 11
  2. B 22
  3. C 33
  4. D 44
Verified Solution

Answer & Solution

Correct Answer

(D) 44

Step-by-step Solution

Detailed explanation

The magnetic flux linked with the circular loop is given by \(\Phi = BA \cos \theta\). Since the plane of the loop is perpendicular to the magnetic field, the angle between the area vector and the magnetic field is \(\theta = 0^{\circ}\). \(\Phi = B \cdot \pi r^2\) Given…
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