JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2026
- Hard
- Numerical
A circular disc has radius \(R_1\) and thickness \(T_1\). Another circular disc made of the same material has radius \(R_2\) and thickness \(T_2\). If the moment of inertia of both discs are same and \(\frac{R_1}{R_2}=2\) then \(\frac{T_1}{T_2}=\frac{1}{\alpha}\).The value of \(\alpha\) is __________ .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) 16
Step-by-step Solution
Detailed explanation
\(I _1= I _2\)
\(\frac{\pi R _1^2 T_1 \rho R _1^2}{2}=\frac{\pi R _2^2 T_2 \rho R _2^2}{2} \Rightarrow \frac{T_1}{T_2}=\frac{1}{16}\)
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