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JEE Mains · Physics · STD 11 - Friction
  • JEE Mains 2024
  • Hard
  • MCQ

A block of mass \(m\) is placed on a surface having vertical cross section given by \(y=x^2 / 4\). If coefficient of friction is \(0.5\) , the maximum height above the ground at which block can be placed without slipping is _______.

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Answer & Solution

Correct Answer

(A) \(1 / 4 \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=\tan \theta=\frac{x}{2}=\mu=\frac{1}{2}\)

\(x=1, y=1 / 4\)

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