JEE Mains · Physics · STD 11 - 4.2 friction
A block of mass \(m\) is placed on a surface having vertical cross section given by \(y=x^2 / 4\). If coefficient of friction is \(0.5\) , the maximum height above the ground at which block can be placed without slipping is _______.
- A \(1 / 4 \mathrm{~m}\)
- B \(1 / 2 \mathrm{~m}\)
- C \(1 / 6 \mathrm{~m}\)
- D \(1 / 3 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(1 / 4 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=\tan \theta=\frac{x}{2}=\mu=\frac{1}{2}\) \(x=1, y=1 / 4\)
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