JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2026
- Easy
- MCQ
A body of mass 2 kg is moving along x -direction such that its displacement as function of time is given by \(x ( t )=\alpha t ^2+\beta t +\gamma m\), where \(\alpha=1 m / s ^2\), \(\beta=1 m / s\) and \(\gamma=1 m\). The work done on the body during the time interval \(t =2 s\) to \(t =3 s\), is _________ J.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) 24
Step-by-step Solution
Detailed explanation
\( x(t)=t^{2}+t+1 \)
\( v(t)=2t+1 \)
\( a(t)=2 \)
\( F=4N. \)
\( Displacement=x(3)-x(2)\)
\(=13-7=6m \)
\( W=F.S=4\times6=24J \)
\( v(t)=2t+1 \)
\( a(t)=2 \)
\( F=4N. \)
\( Displacement=x(3)-x(2)\)
\(=13-7=6m \)
\( W=F.S=4\times6=24J \)
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