JEE Mains · Physics · STD 11 - Friction
- JEE Mains 2022
- Medium
- MCQ
A block of mass \(M\) slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is \(\theta\). The magnitude of the contact force will be.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(Mg\)
Step-by-step Solution
Detailed explanation
\(N = Mg \cos \theta\)
\(f = Mg \sin \theta\)
\(R =\sqrt{ N ^{2}+ f ^{2}}\)
\(R = Mg\)
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