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JEE Mains · Physics · STD 11 - Friction
  • JEE Mains 2022
  • Medium
  • MCQ

A block of mass \(M\) slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is \(\theta\). The magnitude of the contact force will be.

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Answer & Solution

Correct Answer

(A) \(Mg\)

Step-by-step Solution

Detailed explanation

 

\(N = Mg \cos \theta\)

\(f = Mg \sin \theta\)

\(R =\sqrt{ N ^{2}+ f ^{2}}\)

\(R = Mg\)

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