JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A \(100\,m\) long wire having cross-sectional area \(6.25 \times 10^{-4}\,m ^2\) and Young's modulus is \(10^{10}\,Nm ^{-2}\) is subjected to a load of \(250\,N\), then the elongation in the wire will be :
- A \(6.25 \times 10^{-3}\,m\)
- B \(4 \times 10^{-4}\,m\)
- C \(6.25 \times 10^{-6}\,m\)
- D \(4 \times 10^{-3}\,m\)
Answer & Solution
Correct Answer
(D) \(4 \times 10^{-3}\,m\)
Step-by-step Solution
Detailed explanation
Elongation in wire \(\delta=\frac{ F \ell}{ AY }\) \(\delta=\frac{250 \times 100}{6.25 \times 10^{-4} \times 10^{10}}\) \(\delta=4 \times 10^{-3}\,m\)
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