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JEE Mains · Physics · STD 11- Mechanical properties of solids
  • JEE Mains 2023
  • Easy
  • MCQ

A \(100\,m\) long wire having cross-sectional area \(6.25 \times 10^{-4}\,m ^2\) and Young's modulus is \(10^{10}\,Nm ^{-2}\) is subjected to a load of \(250\,N\), then the elongation in the wire will be :

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Answer & Solution

Correct Answer

(D) \(4 \times 10^{-3}\,m\)

Step-by-step Solution

Detailed explanation

Elongation in wire \(\delta=\frac{ F \ell}{ AY }\)

\(\delta=\frac{250 \times 100}{6.25 \times 10^{-4} \times 10^{10}}\)

\(\delta=4 \times 10^{-3}\,m\)

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