JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The shortest distance between the curves \(y^2=8 \mathrm{x}\) and \(x^2+y^2+12 y+35=0\) is :
- A \(2 \sqrt{3}-1\)
- B \(\sqrt{2}\)
- C \(3 \sqrt{2}-1\)
- D \(2 \sqrt{2}-1\)
Answer & Solution
Correct Answer
(D) \(2 \sqrt{2}-1\)
Step-by-step Solution
Detailed explanation
Equation of normal to parabola \(y^2=8 x \text { is } y=m x-4 m-2 m^3\) passes through \((0,-6)\) we get…
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