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JEE Mains · Maths · STD 12 - 13. probability
Given two independent events, if the probability that exactly one of them occurs is \(\frac {26}{49}\) and the probability that none of them occurs is \(\frac {15}{49}\) , then the probability of more probable of the two events is
- A \(4/7\)
- B \(6/7\)
- C \(3/7\)
- D \(5/7\)
Answer & Solution
Correct Answer
(A) \(4/7\)
Step-by-step Solution
Detailed explanation
Let the probability of occurrence of first event \(A,\) be \('a'\) i.e. \(P(A)=a\) \(\therefore P(\text { not } A)=1-a\) And also suppose that probability of occurrence of second event \({\rm{B}},{\rm{P}}({\rm{B}}) = b,\) \(\therefore P(n o t B)-1-b\) Now,…
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