JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
The sum, of the squares of all the roots of the equation \(x^2+|2 x-3|-4=0\), is
- A \(3(3-\sqrt{2})\)
- B \(6(3-\sqrt{2})\)
- C \(6(2-\sqrt{2})\)
- D \(3(2-\sqrt{2})\)
Answer & Solution
Correct Answer
(C) \(6(2-\sqrt{2})\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { For } x \geq \frac{3}{2} \\ & x^2+2 x-3-4=0 \\ & x^2+2 x-7=0 \\ & x=\frac{-2 \pm \sqrt{4+28}}{2}=-1 \pm 2 \sqrt{2}\end{aligned}\) Only \(2 \sqrt{2}-1\) is acceptable root For \(x < \frac{3}{2}\) \(x^2-2 x+3-4=0\)…
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