JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
The minimum distance between any two points \(P _{1}\) and \(P _{2}\) while considering point \(P _{1}\) on one circle and point \(P _{2}\) on the other circle for the given circles' equations \(x^{2}+y^{2}-10 x-10 y+41=0\) \(x^{2}+y^{2}-24 x-10 y+160=0\) is .........
- A \(4\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
Given \(C_{1}(5,5), r_{1}=3\) and \(C_{2}(12,5), r_{2}=3\) Now, \(C_{1} C_{2}>r_{1}+r_{2}\) Thus, \(\left(P_{1} P_{2}\right)_{\min }=7-6=1\)
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