JEE Mains · Maths · STD 11 - 7. binomial theoram
The remainder, when \(7^{103}\) is divided by 23 , is equal to :
- A 6
- B 17
- C 9
- D 14
Answer & Solution
Correct Answer
(D) 14
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & 7^{103}=7\left(7^{102}\right)=7(343)^{34}=7(345-2)^{34} \\ & 7^{103}=23 \mathrm{~K}_1+7.2^{34} \end{aligned}\) Now \(7.2^{34}=7.2^2 \cdot 2^{32}\)…
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