JEE Mains · Maths · STD 12 - 8. Application and integration
The area of the region bounded by the curves \(x\left(1+y^2\right)=1\) and \(y^2=2 x\) is:
- A \(2\left(\frac{\pi}{2}-\frac{1}{3}\right)\)
- B \(\frac{\pi}{2}-\frac{1}{3}\)
- C \(\frac{\pi}{4}-\frac{1}{3}\)
- D \(\frac{1}{2}\left(\frac{\pi}{2}-\frac{1}{3}\right)\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{2}-\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & x\left(1+y^2\right)=1 \\ & y^2=2 x \end{aligned}\) From equation (1) & (2)…
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