ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 10. vector algebra

Let the vectors \(\vec{a} = -\hat{i} + \hat{j} + 3\hat{k}\) and \(\vec{b} = \hat{i} + 3\hat{j} + \hat{k}\). For some \(\lambda, \mu \in \mathbb{R}\), let \(\vec{c} = \lambda \vec{a} + \mu \vec{b}\). If \(\vec{c} \cdot (3\hat{i} - 6\hat{j} + 2\hat{k}) = 10\) and \(\vec{c} \cdot (\hat{i} + \hat{j} + \hat{k}) = -2\), then \(|\vec{c}|^2\) is equal to:

  1. A \(8\)
  2. B \(12\)
  3. C \(14\)
  4. D \(15\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(12\)

Step-by-step Solution

Detailed explanation

Given \(\vec{a} = -\hat{i} + \hat{j} + 3\hat{k}\) and \(\vec{b} = \hat{i} + 3\hat{j} + \hat{k}\). The vector \(\vec{c}\) is given by: \(\vec{c} = \lambda \vec{a} + \mu \vec{b} = (-\lambda + \mu)\hat{i} + (\lambda + 3\mu)\hat{j} + (3\lambda + \mu)\hat{k}\) Using the first…
From JEE Mains
Explore more questions on app